Solve the system of equations 6X negative 3Y equals 6 9x - 3y = -18
To solve this system of equations, we can use the method of substitution or elimination.
Given equations:
1) 6x - 3y = 6
2) 9x - 3y = -18
Let's start by multiplying the first equation by 3 to make the coefficients of y the same:
3 * (6x - 3y) = 3 * 6
18x - 9y = 18
Now we have the equations:
1) 18x - 9y = 18
2) 9x - 3y = -18
Next, we can multiply the second equation by 3 to make the coefficients of y the same as the first equation:
3 * (9x - 3y) = 3 * (-18)
27x - 9y = -54
Now we have the equations:
1) 18x - 9y = 18
2) 27x - 9y = -54
Subtract equation 1 from equation 2 to eliminate y:
27x - 18x - 9y + 9y = -54 - 18
9x = -72
x = -8
Now, substitute x = -8 back into the first equation to solve for y:
6(-8) - 3y = 6
-48 - 3y = 6
-3y = 54
y = -18
Therefore, the solution to the system of equations is x = -8 and y = -18.