A can is in the shape of a cylinder. The can has a volume of 450 cubic inches and a diameter of 4 inches. To the nearest tenth of an inch, what is the height of the can?(1 point) Responses 11.8 in 11.8 in 9 in 9 in 143.2 in 143.2 in 35.8 in
The volume of a cylinder is given by the formula V = πr^2h, where r is the radius of the base and h is the height of the cylinder.
Given that the diameter of the can is 4 inches, the radius would be half of the diameter, so r = 2 inches.
Substitute the values into the formula:
450 = π(2)^2h
450 = 4πh
450 = 12.56h
h = 450 / 12.56
h ≈ 35.8
Therefore, the height of the can is approximately 35.8 inches to the nearest tenth of an inch.
So, the correct answer is 35.8 in.