There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange? answer correctly
The total probability of getting a banana, a pear, and an orange must add up to 1.
Let the probability of getting an orange be x.
So,
5/12 (probability of getting a banana) + 1/6 (probability of getting a pear) + x (probability of getting an orange) = 1
5/12 + 1/6 + x = 1
(5 + 2)/12 + x = 1
7/12 + x = 1
x = 1 - 7/12
x = 12/12 - 7/12
x = 5/12
Therefore, the probability of getting an orange is 5/12.