The volume of a cone is 18π cubic feet. If the height of the cone is 6 ft, what is the radius of the cone? (V = πr^2h)
Given:
Volume (V) = 18π cubic feet
Height (h) = 6 feet
Volume of a cone formula:
V = (1/3)πr^2h
Now, we have:
18π = (1/3)πr^2(6)
Solving for r:
r^2 = (18π * 3) / (6)
r^2 = 54π / 6
r^2 = 9π
r = √(9π)
r = 3√π
Therefore, the radius of the cone is 3√π feet.