What is the distance between (19,−6) and (8,−6) on a coordinate plane?
The distance between two points in a coordinate plane can be found using the distance formula:
√[(x₂ - x₁)² + (y₂ - y₁)²]
In this case, the coordinates are (x₁, y₁) = (19, -6) and (x₂, y₂) = (8, -6). Plugging these values into the formula:
√[(8 - 19)² + (-6 - (-6))²]
√[(-11)² + 0²]
√(121 + 0)
√121
11
Therefore, the distance between the points (19,-6) and (8,-6) on a coordinate plane is 11 units.