Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise at least $400 from the play. Write and graph an inequality for the number of tickets the theater club needs to sell. If the club sells 40 tickets in advance, how many tickets do they need to sell at the door to reach their goal?
3x + 6y greater than or equal to 400 : 40
5x + 4y is greater than or equal to 400; 48
5x + 4y is less than or equal to 400; 48
3x + 6y less than or equal to 400 : 40
Since the theater club sells tickets for $5 at the door and $4 in advance, we can write the inequality as:
5x + 4y ≥ 400
If the club sells 40 tickets in advance, we can substitute y = 40 into the inequality:
5x + 4(40) ≥ 400
5x + 160 ≥ 400
5x ≥ 240
x ≥ 48
So, the theater club needs to sell at least 48 tickets at the door to reach their fundraising goal.