Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the area of the rectangle in square feet.(1 point)
The area of rectangle ABCD is
square feet.
The length of side AB is 3 units and the length of side BC is 5 units. Therefore, the area of the rectangle is 3 x 5 = 15 square units.
However, since the coordinates are in terms of (−5, 1), (−2, 6), etc., we need to consider the units as 3 x 5 = 15 square feet.
So, the area of rectangle ABCD is 15 square feet.