Aquarium I contains 4.6 gallons of water. Louise will begin filling Aquarium I at a rate of 1.2 gallons per minute.
Aquarium II contains 54.6 gallons of water. Isaac will begin draining Aquarium II at a rate of 0.8 gallon per minute.
After how many minutes will both aquariums contain the same amount of water.
(pick an answer)
25 minutes
125 minutes
50 minutes
148 minutes
Let's set up an equation to solve for the time it takes for the two aquariums to contain the same amount of water:
For Aquarium I:
Initial amount of water in Aquarium I = 4.6 gallons
Rate at which water is being added to Aquarium I = 1.2 gallons/minute
Amount of water in Aquarium I after t minutes = 4.6 + 1.2t
For Aquarium II:
Initial amount of water in Aquarium II = 54.6 gallons
Rate at which water is being drained from Aquarium II = 0.8 gallons/minute
Amount of water in Aquarium II after t minutes = 54.6 - 0.8t
Setting the two equations equal to each other:
4.6 + 1.2t = 54.6 - 0.8t
1.2t + 0.8t = 54.6 - 4.6
2t = 50
t = 25
Therefore, it will take 25 minutes for both aquariums to contain the same amount of water. So, the correct answer is 25 minutes.