ph of a 350 ml of a solution that contains 2.64 × 10^-2 mol H+
To calculate the pH of the solution, first calculate the concentration of H+ ions in the solution:
\( \text{Concentration of H}^+ = \frac{2.64 \times 10^{-2} \, \text{mol} }{0.35 \, \text{L}} = 0.0754 \, \text{M} \)
Next, calculate the pH using the formula:
\( \text{pH} = -\log(\text{H}^+) = -\log(0.0754) = 1.12 \)
Therefore, the pH of the solution is 1.12.