Calculate the gradient of the line l .
( 2 )
Y=mx+c
= (x10, y10) and (x5, y5)
Gradient (m) = (y10- y5) / (x10 – x5)
M = y5/x5
= 1
So L = 1
( b ) Write down the equation of the line l .
Since the gradient of the line is 1 and it passes through the point (2,10), we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Substitute x1 = 2, y1 = 10, and m = 1:
y - 10 = 1(x - 2)
y - 10 = x - 2
y = x + 8
Therefore, the equation of the line l is y = x + 8.