Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the area of the rectangle in square feet. (1 point)
To find the area of the rectangle, we will first calculate the length of one side and then multiply it by the length of the other side.
Using the distance formula, we can find the length of side AB:
AB = sqrt((x2 - x1)^2 + (y2 - y1)^2)
AB = sqrt((-2 -(-5))^2 + (1 - 1)^2)
AB = sqrt(3^2 + 0^2)
AB = sqrt(9)
AB = 3 feet
Similarly, we can find the length of side AD:
AD = sqrt((x2 - x1)^2 + (y2 - y1)^2)
AD = sqrt((-5 -(-5))^2 + (6 - 1)^2)
AD = sqrt(0^2 + 5^2)
AD = sqrt(25)
AD = 5 feet
The area of the rectangle is given by:
Area = AB * AD
Area = 3 feet * 5 feet
Area = 15 square feet
Therefore, the area of the rectangle ABCD is 15 square feet.