How many electron’s worth of mass-energy are released in these combined processes Pt-190 reaches to its stable isotope, to the nearest integer?
The combined processes involve the decay of Pt-190 to its stable isotope through alpha decay and the accompanying emission of gamma rays.
The total energy released in these processes can be calculated using the mass-energy equivalence formula, E=mc^2, where m is the mass difference between the initial and final states of the nucleus, and c is the speed of light.
The mass difference between Pt-190 and its stable isotope can be found from nuclear data tables. Let's assume that the mass difference is approximately 0.13 atomic mass units, which is equivalent to 2.15 x 10^-28 kg.
Using the speed of light, c=3.00 x 10^8 m/s, we can calculate the total energy released:
E = (2.15 x 10^-28 kg) * (3.00 x 10^8 m/s)^2
E ≈ 1.94 x 10^-12 J
To convert this energy to electron volts, we can use the conversion factor 1 eV = 1.602 x 10^-19 J:
E = (1.94 x 10^-12 J) / (1.602 x 10^-19 J/eV)
E ≈ 1.21 x 10^7 eV
Therefore, approximately 12.1 million electron volts (eV) worth of mass-energy are released in the combined processes where Pt-190 reaches its stable isotope.