What is the distance between (19,−6) and (8,−6) on a coordinate plane?(1 point)
The distance between two points can be found using the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (19, -6) and (8, -6), so x1 = 19, y1 = -6, x2 = 8, and y2 = -6.
Plugging the values into the formula, we get:
d = √((8 - 19)^2 + (-6 - (-6))^2)
d = √((-11)^2 + (0)^2)
d = √(121 + 0)
d = √121
d = 11
Therefore, the distance between the points (19, -6) and (8, -6) is 11 units.