C3H5N3O9 find empirical formula step by step
Step 1: Find the molar mass of the compound C3H5N3O9
Molar Mass of C: 12.01 g/mol
Molar Mass of H: 1.01 g/mol
Molar Mass of N: 14.01 g/mol
Molar Mass of O: 16.00 g/mol
3(12.01) + 5(1.01) + 3(14.01) + 9(16.00) = 36.03 + 5.05 + 42.03 + 144.00 = 227.11 g/mol
Step 2: Find the number of moles of each element in the compound:
Number of moles of C = 3 moles
Number of moles of H = 5 moles
Number of moles of N = 3 moles
Number of moles of O = 9 moles
Step 3: Divide the number of moles of each element by the smallest number of moles:
Number of moles of C = 3/3 = 1
Number of moles of H = 5/3 ≈ 1.67
Number of moles of N = 3/3 = 1
Number of moles of O = 9/3 = 3
Step 4: Round the ratio to the nearest whole number to obtain the empirical formula:
C1H1.67N1O3
Step 5: Multiply each subscript in the formula by 3 to get rid of the fraction:
C3H5N3O9
Therefore, the empirical formula of C3H5N3O9 is C3H5N3O9.