Water, with a density of p=1135 kg/m^3, flows in a horizontal pipe. In one segment of the pipe, the flow speed is v1=6.73 m/s. In a second segment, the flow speed is v2= 2.37 m/s. What is the difference between the pressure P2 in the second segment an the pressure P1 in the first segment?
To find the difference in pressure between the two segments, we can use Bernoulli's equation:
P1 + 1/2 ρv1^2 = P2 + 1/2 ρv2^2
Where:
P1 = pressure in the first segment
P2 = pressure in the second segment
ρ = density of water = 1135 kg/m^3
v1 = flow speed in first segment = 6.73 m/s
v2 = flow speed in second segment = 2.37 m/s
Now we can plug in the values and solve for the pressure difference:
P1 + 1/2 * 1135 * 6.73^2 = P2 + 1/2 * 1135 * 2.37^2
P1 + 70962.305 = P2 + 14959.755
P1 - P2 = 70962.305 - 14959.755
P1 - P2 = 56002.55
Therefore, the pressure difference between the two segments is 56002.55 Pa.