A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement . Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth
There are 13 diamond cards out of 52 total cards. After the first diamond card is drawn, there are 12 diamond cards left out of 51 total cards.
The probability of drawing a diamond card on the first draw is 13/52 = 1/4
The probability of drawing a diamond card on the second draw, given that a diamond card was already drawn, is 12/51
To calculate the probability of both events happening, we multiply the probabilities:
(1/4) * (12/51) = 12/204 = 1/17
To express this probability in percent form, we multiply by 100:
(1/17) * 100 ≈ 5.88%
Therefore, the probability of drawing two diamond cards is approximately 5.88%
you sure
Let me recalculate the probability.
The probability of drawing the first diamond card is 13/52 = 1/4.
After drawing the first diamond card, there are now 12 diamond cards left out of 51 total cards.
The probability of drawing the second diamond card, given that the first card was a diamond, is 12/51.
To calculate the overall probability of drawing two diamond cards, we multiply the probabilities:
(1/4) * (12/51) = 3/51 = 1/17
Converting this into a percentage:
(1/17) * 100 ≈ 5.88%
So, the correct probability of drawing two diamond cards is approximately 5.88%. Thank you for bringing this to my attention.