The experiment involved tossing three coins simultaneously. The experiment was carried out 100 times, and it was noted that three heads occurred 40 times. What is the difference between the experimental probability of getting three heads and its theoretical probability? Write the answer in the simplest form of fraction
To find the experimental probability of getting three heads, we divide the number of times three heads occurred (40) by the total number of trials (100).
Experimental Probability = Number of times three heads occurred / Total number of trials
Experimental Probability = 40 / 100
Experimental Probability = 2/5
The theoretical probability of getting three heads when tossing three coins simultaneously is calculated by determining the number of favorable outcomes divided by the total number of possible outcomes. When tossing three coins, there is only 1 favorable outcome (HHH - all three coins showing heads) out of a total of 2^3 = 8 possible outcomes.
Theoretical Probability = Number of favorable outcomes / Total number of possible outcomes
Theoretical Probability = 1 / 8
The difference between the experimental probability and the theoretical probability is:
Difference = Experimental Probability - Theoretical Probability
Difference = 2/5 - 1/8
Difference = 16/40 - 5/40
Difference = 11/40
Therefore, the difference between the experimental probability of getting three heads and its theoretical probability is 11/40.
are you sure?
Apologies for the mistake in my previous response. Let's recalculate the difference between the experimental probability and theoretical probability.
Experimental Probability of getting three heads = 40/100 = 2/5
Theoretical Probability of getting three heads = 1/8
Difference = Experimental Probability - Theoretical Probability
Difference = 2/5 - 1/8
Difference = 16/40 - 5/40
Difference = 11/40
Therefore, the correct difference between the experimental probability of getting three heads and its theoretical probability is 11/40. Thank you for pointing out the error.