The table shows the linear relationship between the distance in feet below sea level and the time in seconds traveled by a submarine. What is the rate of change of the distance in feet below sea level with respect to time that the submarine traveled?
heres the table x is on the left
0 460
18 604
34 732
52 876
70 1020
To find the rate of change of the distance in feet below sea level with respect to time, we first need to find the average rate of change over the intervals given in the table.
Average rate of change = Change in distance / Change in time
For the interval between (0, 460) and (18, 604):
Average rate of change = (604 - 460) / (18 - 0) = 144 / 18 = 8
For the interval between (18, 604) and (34, 732):
Average rate of change = (732 - 604) / (34 - 18) = 128 / 16 = 8
For the interval between (34, 732) and (52, 876):
Average rate of change = (876 - 732) / (52 - 34) = 144 / 18 = 8
For the interval between (52, 876) and (70, 1020):
Average rate of change = (1020 - 876) / (70 - 52) = 144 / 18 = 8
The rate of change of the distance in feet below sea level with respect to time that the submarine traveled is 8 feet per second.