f(x) = 6e^(-5x) ln(x), find f'(3)?
You have to use both the product rule and the "chain" rule.
f'(x) = lnx*6*e^(-5x)*(-5) + (6/x)e^(-5x)
= e^(-5x)[-30 lnx + (6/x)]
Plug in x = 3 to get f'(3)
e^-15 = 3.059*10^-7
-30 lnx = -32.96
6/x = 2
f'(x) = lnx*6*e^(-5x)*(-5) + (6/x)e^(-5x)
= e^(-5x)[-30 lnx + (6/x)]
Plug in x = 3 to get f'(3)
e^-15 = 3.059*10^-7
-30 lnx = -32.96
6/x = 2