Using this example:hat is the radius of a sphere with a volume of 21044, cm, cubed, comma21044 cm
3
, to the nearest tenth of a centimeter?
Volume of a Sphere:
Volume of a Sphere:
V, equals, start fraction, 4, divided by, 3, end fraction, pi, r, cubed
V=
3
4
πr
3
21044, equals, left bracket, start fraction, 4, divided by, 3, end fraction, pi, right bracket, r, cubed
21044=
(
3
4
π)r
3
21044, equals, left bracket, 4, point, 1, 8, 8, 7, 9, 0, 2, right bracket, r, cubed
21044=
(4.1887902)r
3
Evaluate 4/3pi in calc
start fraction, 2, 1, 0, 4, 4, divided by, 4, point, 1, 8, 8, 7, 9, 0, 2, end fraction, equals, start fraction, left bracket, 4, point, 1, 8, 8, 7, 9, 0, 2, right bracket, r, cubed, divided by, 4, point, 1, 8, 8, 7, 9, 0, 2, end fraction
4.1887902
21044
=
4.1887902
(4.1887902)r
3
Evaluate start fraction, 4, divided by, 3, end fraction, pi
3
4
π in calc
5023, point, 8, 8, 4, 9, 3, 3, 6, equals, r, cubed
5023.8849336=
r
3
cube root of, 5023, point, 8, 8, 4, 9, 3, 3, 6, end cube root, equals, cube root of, r, cubed, end cube root
3
5023.8849336
=
3
r
3
Cube root both sides
17, point, 1, 2, 6, 9, 4, 4, 7, equals, r
17.1269447=
r
Final Answer:
Final Answer:
r, approximately equals, 17, point, 1, cm
r≈17.1 cm
Solve this problom What is the diameter of a sphere with a volume of 944^3, to the nearest tenth of a centimeter?
To find the diameter of a sphere, we first need to find the radius using the formula for the volume of a sphere:
V = (4/3)πr^3
Given that the volume of the sphere is 944^3, we have:
944 = (4/3)πr^3
Solving for r, we get:
r = cube root of (944 / ((4/3)π))
r ≈ 5.32 cm
The diameter of the sphere is twice the radius, so:
Diameter ≈ 2 * 5.32 ≈ 10.64 cm
Therefore, the diameter of the sphere with a volume of 944^3 is approximately 10.64 cm.
your wrong
I apologize for the mistake in my previous response. Let's correctly calculate the diameter of the sphere with a volume of 944 cm^3.
Given the volume of the sphere is 944 cm^3, we have:
V = (4/3)πr^3
944 = (4/3)πr^3
Now, solve for r:
r = cube root of (944 / ((4/3)π))
r = cube root of (944 / (4.1887902))
r = cube root of 224.99556
r ≈ 6.88 cm
The diameter of the sphere is twice the radius, so:
Diameter = 2 * 6.88 ≈ 13.76 cm
Therefore, the diameter of the sphere with a volume of 944 cm^3 is approximately 13.76 cm. Thank you for pointing out the error, and I hope this revised calculation is helpful.