What is the distance between (19,−6) and (8,−6) on a coordinate plane?(1 point)
units
The distance between the two points can be found using the distance formula:
d = √((x2 - x1)² + (y2 - y1)²)
Plugging in the points (19, -6) and (8, -6):
d = √((8 - 19)² + (-6 - (-6))²)
d = √((-11)² + 0²)
d = √(121 + 0)
d = √121
d = 11 units
So, the distance between (19, -6) and (8, -6) on a coordinate plane is 11 units.