The equation is written in point-slope form.
y+3=1/3(x-5)
Find a point on the line and the line's slope.
point on the line:
slope:
A point on the line can be found by setting y+3=0 in the equation:
0 + 3 = 1/3(x-5)
3 = 1/3(x-5)
9 = x - 5
x = 14
Therefore, a point on the line is (14, -3).
To find the line's slope, we can rewrite the equation in slope-intercept form (y=mx+b) by solving for y:
y + 3 = 1/3(x-5)
y = 1/3(x-5) - 3
y = 1/3x - 5/3 - 3
y = 1/3x - 5/3 - 9/3
y = 1/3x - 14/3
Comparing this equation to y=mx+b, we see that the slope (m) of the line is 1/3.
point on the line is wrong
I apologize for the mistake. Let's correct that.
To find a point on the line, we can rewrite the equation in point-slope form as:
y + 3 = (1/3)(x - 5)
From the equation, we have the y-coordinate of the point as -3 (since y +3 = 0):
-3 + 3 = (1/3)(x - 5)
0 = (1/3)(x - 5)
0 = x - 5
x = 5
Therefore, a point on the line is (5, -3).
The slope of the line can be obtained from the coefficient of x in the equation, which is 1/3. So, the slope of the line is 1/3.