or
Solve using substitution.
y = –3
10x + 9y = –17
To solve this system of equations using substitution, we will substitute y = -3 into the second equation and solve for x:
10x + 9(-3) = -17
10x - 27 = -17
10x = -17 + 27
10x = 10
x = 10/10
x = 1
Therefore, the solution to the system of equations y = -3 and 10x + 9y = -17 is x = 1 and y = -3.
Solve using substitution.
x = 3
x + 2y = 1
To solve this system of equations using substitution, we substitute x = 3 into the second equation and solve for y:
3 + 2y = 1
2y = 1 - 3
2y = -2
y = -2/2
y = -1
Therefore, the solution to the system of equations x = 3 and x + 2y = 1 is x = 3 and y = -1.
Solve using substitution.
y = –5x − 10
y = –x + 6
Since both equations are equal to y, we can set them equal to each other and solve for x:
−5x − 10 = −x + 6
Rearranging terms:
−5x + x = 6 + 10
-4x = 16
Divide by -4 on both sides:
x = -4
Now substitute x = -4 into either equation to solve for y:
y = -5(-4) - 10
y = 20 - 10
y = 10
Therefore, the solution to the system of equations is x = -4 and y = 10.
Solve using substitution.
y = 6
–5x + 6y = 6
Substitute y = 6 into the second equation and solve for x:
-5x + 6(6) = 6
-5x + 36 = 6
-5x = 6 - 36
-5x = -30
x = -30 / -5
x = 6
Therefore, the solution to the system of equations y = 6 and -5x + 6y = 6 is x = 6 and y = 6.
Solve using substitution.
y = 2x + 6
y = –2x + 2
Since both equations are equal to y, we can set them equal to each other and solve for x:
2x + 6 = -2x + 2
Rearranging terms:
2x + 2x = 2 - 6
4x = -4
x = -4 / 4
x = -1
Now substitute x = -1 back into one of the original equations to solve for y:
y = 2(-1) + 6
y = -2 + 6
y = 4
Therefore, the solution to the system of equations is x = -1 and y = 4.
Solve using substitution.
–6x + 6y = 6
–2x + y = 11