A number has a remainder of 2 when divided by 5 and also has a remainder of two when divided by 3. Please find the biggest possible value of this two digit number.
To find the biggest possible value of this two digit number, we first need to find a number that satisfies both conditions.
Let's call the number we are looking for "x".
We know that x divided by 5 gives a remainder of 2, so we can write x = 5n + 2, where n is an integer.
We also know that x divided by 3 gives a remainder of 2, so we can write x = 3m + 2, where m is an integer.
Now we have two equations:
5n + 2 = 3m + 2
5n = 3m
Since we are looking for a two digit number, n must be greater than or equal to 2 (since the remainder when divided by 5 will be at least 2).
The biggest possible value of n can be 2, which gives us:
x = 5(2) + 2 = 12
Therefore, the biggest possible value of this two digit number is 12.