The table shows the results of rolling a number cube with sides labeled 1 through 6 several times.
What is the experimental probability of rolling a 3 or a 6?
Enter your answer as a fraction in simplest form in the box.
$\text{Basic}$$x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$$x\frac{ }{ }$$x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$
Outcome Number of times outcome occurred
1 10
2 6
3 4
4 8
5 6
6 6
The total number of rolls is 10 + 6 + 4 + 8 + 6 + 6 = 40.
The number of times a 3 or a 6 was rolled is 4 + 6 = 10.
So, the experimental probability of rolling a 3 or a 6 is 10/40 = 1/4.
Therefore, the answer is \(\frac{1}{4}\)