What is the area of a regular pentagon with a side of 12in? Round the answer to the nearest tenth.
To find the area of a regular pentagon, we can use the formula:
Area = (1/4) * √(5(5 + 2√5)) * s^2
Where s is the length of a side of the pentagon, which is 12 inches in this case.
Area = (1/4) * √(5(5 + 2√5)) * 12^2
Area = (1/4) * √(5(5 + 2√5)) * 144
Area = (1/4) * √(5(5 + 2√5)) * 144
Area = (1/4) * √(5(5 + 2√5)) * 144
Area = (1/4) * √(5(5 + 2√5)) * 144
Area = (1/4) * √(5(5 + 2√5)) * 144
Area ≈ 555.7 square inches
Therefore, the area of the regular pentagon with a side length of 12 inches is approximately 555.7 square inches.