How much volume of a solution of AgNOs, 0.100 M, is needed to transfer 0.030 mol AgNOs? {Ans: 300 mL of AgNO3, 0.100 M) Write the set up that justifies the answer.
The amount of solution needed can be calculated using the formula:
Volume (V) = moles (n) / molarity (M)
Given:
moles (n) = 0.030 mol
molarity (M) = 0.100 M
Substitute the values into the formula:
V = 0.030 mol / 0.100 M
V = 0.300 L
Since the answer is usually expressed in milliliters, convert liters to milliliters:
V = 300 mL
Therefore, 300 mL of AgNO3, 0.100 M solution is needed to transfer 0.030 mol of AgNO3.