Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. X^2 + 3= -4x
First, rearrange the equation to standard form:
x^2 + 4x + 3 = 0
Now, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 1, b = 4, and c = 3. Plugging in the values:
x = (-4 ± √(4^2 - 4*1*3)) / 2*1
x = (-4 ± √(16 - 12)) / 2
x = (-4 ± √4) / 2
x = (-4 ± 2) / 2
Now we have two possible solutions:
x = (-4 + 2) / 2 = -2 / 2 = -1
x = (-4 - 2) / 2 = -6 / 2 = -3
So the solutions to the equation x^2 + 3 = -4x are x = -1 and x = -3.