Suppose you are a solving a quadratic equation using the quadratic formula and this is your work so far:

3x^{2}+4x-1=0
x=\frac{-4\ \pm\sqrt{\left(4\right)^{2}-4\left(3\right)\left(-1\right)}}{2\left(3\right)}
x=\frac{-4\ \pm\sqrt{???}}{6}

What number goes in place of ???

13