Given the equation y = 3/4x - 6 .
Part II: Write TWO equations of lines in slope-intercept form that are PERPENDICULAR to the given line, y = 3/4x - 6. Then EXPLAIN how you know the equations you chose are perpendicular.
Line One: y=____________
Line Two: y =____________
Line One: y = -4/3x + 2
Line Two: y = 4/3x + 10
To determine the equations that are perpendicular to the given line y = 3/4x - 6, we need to find the negative reciprocal of the slope. The slope of the given line is 3/4, so the negative reciprocal is -4/3.
Therefore, the equations y = -4/3x + b and y = 4/3x + b (where b is the y-intercept) will be perpendicular to the given line.