A 1.0 mole sample of HN03 is added to water. The final volume of the solution is 1.5 L in the final temperature of the solution is 25°C. Calculate the pOH of the solution.
To calculate the pOH of the solution, we first need to calculate the concentration of OH- ions in the solution.
Given that 1 mole of HNO3 produces 1 mole of H+ ions, the concentration of H+ ions in the solution is 1.0 M.
Since HNO3 is a strong acid, it completely dissociates into H+ and NO3- ions:
HNO3 → H+ + NO3-
Since HNO3 is a monoprotic acid, the concentration of H+ ions is equal to the concentration of NO3- ions.
Therefore, the concentration of OH- ions in the solution is equal to the concentration of H+ ions, which is 1.0 M.
Using the formula pOH = -log[OH-], we can calculate the pOH of the solution:
pOH = -log(1.0) = -0 = 0
Therefore, the pOH of the solution is 0.