A metal stays solid at Fahrenheit temp below 1868.5
Determine (in terms of an inequality) those Celsisu temp, for which the metal stays solid. Use the formula
F=9/5c+32
1868.5 = (9/5)c + 32
multiply by 5
9342.5 = 9c + 160
solve for c
then change to inequality
cIc<1020.28
Thanks!
To determine the Celsius temperature for which the metal stays solid, we can use the formula F = (9/5)C + 32, where F is the Fahrenheit temperature and C is the Celsius temperature.
Given that the metal stays solid at Fahrenheit temperatures below 1868.5, we can set up the following inequality:
F < 1868.5
Substituting F with the formula (9/5)C + 32, we get:
(9/5)C + 32 < 1868.5
To isolate C, we can start by subtracting 32 from both sides of the inequality:
(9/5)C < 1868.5 - 32
(9/5)C < 1836.5
Then, to solve for C, we can multiply both sides of the inequality by 5/9:
C < (1836.5)(5/9)
C < 1019.166...
So, in terms of an inequality, the Celsius temperature for which the metal stays solid can be expressed as:
C < 1019.166...
To determine the Celsius temperature for which the metal stays solid, we can use the given formula to relate Fahrenheit and Celsius temperatures:
F = (9/5)C + 32
Since we want to find the Celsius temperature range for which the metal stays solid, we need to rearrange the formula to solve for C:
C = (5/9)(F - 32)
Now we can substitute the given condition that the metal stays solid below 1868.5 Fahrenheit into our formula:
C = (5/9)(1868.5 - 32)
Simplifying further:
C = (5/9)(1836.5)
C ≈ 1020.2778
Therefore, the inequality representing the Celsius temperatures for which the metal stays solid is:
C ≤ 1020.2778