What is the volume percent in ethanol obtained by the fermentation of sugar by yeast, if a 50-mL aliquot of the fermented liquid contains 6.3 mL of ethanol?
To find the volume percent of ethanol in the fermented liquid, we can use the formula:
Volume percent = (volume of ethanol / total volume) x 100
Given that the total volume of the fermented liquid is 50 mL, and the volume of ethanol is 6.3 mL, we can substitute these values into the formula:
Volume percent = (6.3 mL / 50 mL) x 100
Volume percent = (0.126) x 100
Volume percent = 12.6%
Therefore, the volume percent of ethanol in the fermented liquid is 12.6%.