On a standardized exam, the scores are normally distributed with a mean of 650 and a standard deviation of 20. Find the -score of a person who scored 650 on the exam.
The z-score formula is:
z = (X - μ) / σ
Where:
X = individual score
μ = mean of the distribution
σ = standard deviation
Given:
X = 650
μ = 650
σ = 20
Plugging in the values:
z = (650 - 650) / 20
z = 0 / 20
z = 0
Therefore, the z-score of a person who scored 650 on the exam is 0.