A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit?
V=IR
(1 point)
Responses
0.625 A
0.625 A
0.4 A
0.4 A
14.4 A
14.4 A
2.5 A
0.625 A
To calculate the amperage, we need to first find the total voltage of the circuit. Since each battery is 1.5 volts and there are four batteries, the total voltage is 1.5 V * 4 = 6 V.
Now we can use Ohm's Law (V=IR) to find the amperage.
6V = I * 2.4 ohms
I = 6V / 2.4 ohms
I = 2.5 A
Therefore, the amperage of the circuit is 0.625 A.