Use the image to answer the question.
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
inches2
The surface area of the net diagram of the right circular cylinder can be calculated by adding the areas of the two circles and the rectangle.
The area of a circle is given by the formula A = πr^2, where r is the radius. Therefore, the area of one circle is 3.14*10^2 = 314 square inches. Since there are two circles, the total area of the circles is 2*314 = 628 square inches.
The area of the rectangle is given by the formula A = l * w, where l is the length and w is the width. In this case, the length is 9 inches and the width is 10 inches. Therefore, the area of the rectangle is 9*10 = 90 square inches.
Adding the area of the circles and the rectangle, the total surface area of the net diagram of the right circular cylinder is 628 + 90 = 718 square inches.
Therefore, the surface area of the net diagram of the right circular cylinder is 718 square inches.