Use the image to answer the question.
An illustration shows an arrow pointing both right and left. It is formed by triangles on the right and left connected by a rectangle in the middle. The length of the rectangle measures 16 inches, and the width measures 3 inches. The perpendicular height of the triangle on the right is shown by a horizontal dotted line from the right vertex to the base. The perpendicular height measures 8 inches. The length of the base of the triangle measures 10 inches.
A school hallway has a bidirectional arrow showing which way traffic can move. The dimensions of the sign are shown. What is the arrow’s area?
(1 point)
Responses
208 in.2
208 in. squared
80 in.2
80 in. squared
128 in.2
128 in. squared
48 in.2
The area of the bidirectional arrow can be calculated by finding the area of both triangles and the rectangle and then adding them together.
Area of triangle on the right = 1/2 * base * height
Area of triangle on the right = 1/2 * 10 * 8 = 40 in^2
Area of triangle on the left = 1/2 * base * height
Area of triangle on the left = 1/2 * 10 * 8 = 40 in^2
Area of rectangle = length * width
Area of rectangle = 16 * 3 = 48 in^2
Total area of the bidirectional arrow = 40 + 40 + 48 = 128 in^2
Therefore, the correct answer is 128 in^2.