There is a jar that contains 9 marbles and 3 of them are blue. If you were to randomly draw 2 marbles (with replacement) what is the probability that both are the marbles are not blue? Write your answer as a fraction. You do not need to simplify your faction
The probability of drawing a non-blue marble on the first draw is $\frac{6}{9}$. Since we are replacing the marble after each draw, the probability of drawing a non-blue marble on the second draw is also $\frac{6}{9}$.
Therefore, the probability of drawing two non-blue marbles is $\frac{6}{9} \times \frac{6}{9} = \frac{36}{81}$.