Trend Lines Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
5 of 55 of 5 Items
Question
Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
To write the equation of the trend line in slope-intercept form, we first need to determine the slope of the line. The slope can be calculated using two points on the line, such as (0,12) and (6,18).
slope = (change in y) / (change in x)
slope = (18 - 12) / (6 - 0)
slope = 6 / 6
slope = 1
Next, we can use the slope-intercept form of an equation, y = mx + b, where m is the slope and b is the y-intercept. To find the y-intercept, we can use the point (0,12).
12 = 1(0) + b
b = 12
Therefore, the equation of the trend line in slope-intercept form is:
y = x + 12