How many zinc atoms are present in 32.0g of zinc?
Using the molar mass of zinc (65.38 g/mol), we can calculate the number of moles of zinc in 32.0g:
32.0g รท 65.38 g/mol = 0.49 mol
Since 1 mol of zinc contains 6.022 x 10^23 atoms, we can calculate the number of zinc atoms in 0.49 mol:
0.49 mol x 6.022 x 10^23 atoms/mol = 2.95 x 10^23 atoms
Therefore, there are approximately 2.95 x 10^23 zinc atoms present in 32.0g of zinc.