Systems of Linear Equations Unit Test 8 of 158 of 15 Items Question Solve the system of equations. 4x−8y=−36 −6x+y=32 (1 point)
To solve the system of equations:
4x - 8y = -36 (1)
-6x + y = 32 (2)
First, we can rewrite equation (2) in terms of y:
y = 32 + 6x
Now, we can substitute this expression for y into equation (1) and solve for x:
4x - 8(32 + 6x) = -36
4x - 256 - 48x = -36
-44x - 256 = -36
-44x = 220
x = -5
Now we can substitute the value of x back into equation (2) to solve for y:
-6(-5) + y = 32
30 + y = 32
y = 2
Therefore, the solution to the system of equations is x = -5 and y = 2.