How many grams of NaOH are present in 3.1 moles of NaOH. (The molar mass of NaOH is 39.997 grams/mol) If you are unsure how to convert moles to grams, please see the example problem linked HERE. a 0.078 grams of NaOH b 12.90 grams of NaOH c 123.99 grams of NaOH d 43.10 grams of NaOH
The correct answer is b) 12.90 grams of NaOH.
To calculate the grams of NaOH present in 3.1 moles, use the formula:
Grams = Moles x Molar Mass
Grams = 3.1 moles x 39.997 grams/mol = 123.99 grams
Therefore, there are 123.99 grams of NaOH in 3.1 moles of NaOH.