Calcium carbonate ( CaCO3
) can undergo a chemical reaction to produce calcium oxide ( CaO
) and carbon dioxide ( CO2
). Which possible masses of calcium oxide and carbon dioxide can form when 200g of calcium carbonate undergoes this chemical reaction?(1 point)
Responses
112g CaO
and 88g CO2
112g cap c A cap o and 88g cap c cap o sub 2
200g CaO
and 200g CO2
200g cap c A cap o and 200g cap c cap o sub 2
56g CaO
and 44g CO2
56g cap c A cap o and 44g cap c cap o sub 2
40g CaO
and 12g CO2
40g cap c A cap o and 12g cap c cap o sub 2
The correct answer is:
112g CaO and 88g CO2
This can be determined by stoichiometry based on the balanced chemical equation for the reaction:
CaCO3 → CaO + CO2
Using the molar masses of each compound:
CaCO3: 100.09 g/mol
CaO: 56.08 g/mol
CO2: 44.01 g/mol
First, calculate the number of moles of CaCO3 in 200g:
200g CaCO3 / 100.09 g/mol = 1.999 moles CaCO3
From the balanced equation, 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2. Therefore, 1.999 moles of CaCO3 will produce 1.999 moles of CaO and 1.999 moles of CO2.
Calculate the mass of each product:
1.999 moles CaO x 56.08 g/mol = 112.06g CaO
1.999 moles CO2 x 44.01 g/mol = 88.00g CO2
Therefore, the possible masses of calcium oxide and carbon dioxide that can form when 200g of calcium carbonate undergoes this chemical reaction are 112g CaO and 88g CO2.