What is the distance covered by the skydiver after 5 seconds if his initial velocity was 0 m/s? Assume F drag = 0 and acceleration due to gravity is 10 m/s 2 .
Using the equation of motion:
distance covered = (1/2) * acceleration * time^2
Plugging in the values, we get:
distance covered = (1/2) * 10 m/s^2 * (5 s)^2
distance covered = 125 meters
Therefore, the skydiver covers a distance of 125 meters after 5 seconds.