A pendulum swinging back and forth loses momentum and distance with each oscillation. The total distance the pendulum swings on the first oscillation is 12 inches, and the distance of each consecutive oscillation is 23%0D%0A2%0D%0A3%0D%0A of the previous distance. What distance will the pendulum travel on the fifth oscillation, measured to the nearest whole inch?%0D%0A%0D%0A(1 point)%0D%0AIn the fifth oscillation, the pendulum will travel approximately inches.
To find the distance the pendulum travels on the fifth oscillation, we need to calculate the distance for each oscillation leading up to the fifth.
1st oscillation: 12 inches
2nd oscillation: 12 * 0.23 = 2.76 inches
3rd oscillation: 2.76 * 0.23 = 0.6348 inches
4th oscillation: 0.6348 * 0.23 = 0.145884 inches
Now, we can find the total distance traveled by summing the distances for each oscillation up to the fourth:
Total distance = 12 + 2.76 + 0.6348 + 0.145884 ≈ 15.54 inches
Therefore, in the fifth oscillation, the pendulum will travel approximately 15 inches (rounded to the nearest whole inch).