Let a=x^2+4. Rewrite the following equation in terms of a and set it equal to zero.
(x^2+4)^2+32=12x^2+48
In the resulting equation what is the coefficient of the a term? In the resulting equation, what is the constant?
First, let's rewrite the equation in terms of a:
a^2 + 32 = 12a + 48
Now, we can rewrite this equation as a quadratic equation in terms of a:
a^2 - 12a + 16 = 0
In this quadratic equation, the coefficient of the a term is -12 and the constant is 16.