Elements A and B react according to the following balanced equation.
3A2+2B → 2A3B
The molar mass of element A is 4g/mol. The molar mass of element B is 16g/mol. When the initial mass of element A is 48g, which mass of element B should be present?
(1 point)
Responses
64g
64g
128g
128g
192g
192g
96g
In order to determine the mass of element B present, we need to first calculate the number of moles of A present using its molar mass (4 g/mol) and initial mass (48 g):
Number of moles of A = 48 g / 4 g/mol = 12 mol
From the balanced chemical equation, the mole ratio of A to B is 3:2. Therefore, the number of moles of B can be calculated using the mole ratio:
Number of moles of B = 12 mol * (2/3) = 8 mol
Finally, to determine the mass of element B present, we use its molar mass (16 g/mol):
Mass of B present = 8 mol * 16 g/mol = 128 g
Therefore, the correct answer is 128g.