Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75%0D%0A%0D%0A=%0D%0A50%0D%0A%0D%0A+%0D%0A75%0D%0A , where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?(1 point)%0D%0AResponses%0D%0A%0D%0ACharles pays $300 for a 3-hour trip.%0D%0ACharles pays $300 for a 3-hour trip.%0D%0A%0D%0ACharles can go on a 1-hour fishing trip for less than $100.%0D%0ACharles can go on a 1-hour fishing trip for less than $100.%0D%0A%0D%0AFor $200, Charles can travel for 2 hours.%0D%0AFor $200, Charles can travel for 2 hours.%0D%0A%0D%0ACharles can take a 6-hour trip for less than $400.

Based on the line of best fit, we can predict that Charles can take a 6-hour trip for less than $400. This prediction is based on the equation y=50x+75, where y represents the price of the trip and x represents the number of hours. Plugging in x=6, we get y=50(6)+75=300+75=375. Therefore, Charles can take a 6-hour trip for less than $400.