What is the [H+] if the solution has a pH=2.88
[H+] = 10^(-pH)
[H+] = 10^(-2.88)
[H+] = 1.41 x 10^(-3) M
Therefore, the [H+] of the solution with a pH of 2.88 is 1.41 x 10^(-3) M.
[H+] = 10^(-2.88)
[H+] = 1.41 x 10^(-3) M
Therefore, the [H+] of the solution with a pH of 2.88 is 1.41 x 10^(-3) M.