Calculate the volume of the gas when the pressure of the gas is 1.20 atm
at a temperature of 298 K
. There are 150. mol
of gas in the container. The value for the universal gas constant R
is 0.08206 L⋅atm/(mol⋅K)
.
To calculate the volume of the gas, we can use the ideal gas law:
PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the universal gas constant, and T is the temperature of the gas.
Given:
P = 1.20 atm
n = 150 mol
R = 0.08206 L⋅atm/(mol⋅K)
T = 298 K
Plugging in the values:
1.20 atm * V = 150 mol * 0.08206 L⋅atm/(mol⋅K) * 298 K
V = (150 * 0.08206 * 298) / 1.20
V = 3046.73 L
Therefore, the volume of the gas when the pressure is 1.20 atm and the temperature is 298 K with 150 mol of gas in the container is 3046.73 liters.